S1, S2, S3 are net complex power injections into bus 1, 2, 3 respectively
y12, y23, y13 are line admittances between lines 1-2, 2-3, 1-3
y01sh/2, y02sh/2, y03sh/2 are half-line charging admittance between lines 1-2, 1-3 and 2-3
The half-line charging admittances connected to the same bus are at same potential and thus can be combined into one
If we apply KCL at bus 1, we have
Where, V1, V2, V3 are voltage values at bus 1, 2, 3 respectively
Where,
Similarly by applying KCL at buses 2 and 3 we can derive the values of I2 and I3
Finally we have
In general for an n bus system
Some observations on YBUS matrix:
YBUS is a sparse matrix
Diagonal elements are dominating
Off diagonal elements are symmetric
The diagonal element of each node is the sum of the admittances connected to it
The off diagonal element is negated admittance
The net complex power injection at bus i is given by:
Taking conjugate
Substituting the value of Ii in equation (2)
To derive the static load flow equation in polar form in equation (4) substitute
On substitution of the above values equation (4) becomes
In equation (5) on multiplication of the terms angles get added. Let’s denotefor convenience
Therefore equation (5) becomes
Expansion of equation (6) into sine and cosine terms gives
Equating real and imaginary parts we get
Equations (7) and (8) are the static load flow equations in polar form. The above obtained equations are non-linear algebraic equations and can be solved using iterative numerical algorithms.
Similarly to obtain load flow equations in rectangular form in equation (4) substitute
On substituting above values into equation (4) and equating real and imaginary parts we get
Equations (9) and (10) are static load flow equations in rectangular form.
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